# Complementarity problem

### From Wikimization

(In particular, we can have everywhere in this page.)

## Fixed point problems

Let be a set and a mapping. The **fixed point problem** defined by is the problem

## Nonlinear complementarity problems

Let be a closed convex cone in the Hilbert space and a mapping. Recall that the dual cone of is the closed convex cone where is the polar of The **nonlinear complementarity problem** defined by and is the problem

## Every nonlinear complementarity problem is equivalent to a fixed point problem

Let be a closed convex cone in the Hilbert space and a mapping. Then the nonlinear complementarity problem is equivalent to the fixed point problem where is the identity mapping defined by and is the projection onto

### Proof

For all denote and Then

Suppose that is a solution of Then with
and Hence, via Moreau's theorem, we get Therefore is a solution of

Conversely, suppose that is a solution of Then and via Moreau's theorem

Hence thus Moreau's theorem also implies that In conclusion, and Therefore is a solution of

### An alternative proof without Moreau's theorem

#### Variational inequalities

Let be a closed convex set in the Hilbert space and a mapping. The **variational inequality** defined by and is the problem

##### Remark

The next result is not needed for the alternative proof and it can be skipped. However, it is an important property in its own. It was included for the completeness of the ideas.

#### Every fixed point problem defined on closed convex set is equivalent to a variational inequality

Let be a closed convex set in the Hilbert space and a mapping. Then the fixed point problem is equivalent to the variational inequality where

##### Proof

Suppose that is a solution of . Then, and thus is a solution of

Conversely, suppose that is a solution of and let Then, which is equivalent to Hence, ; that is, is a solution of .

#### Every variational inequality is equivalent to a fixed point problem

Let be a closed convex set in the Hilbert space and a mapping. Then the variational inequality is equivalent to the fixed point problem

##### Proof

is a solution of if and only if Via characterization of the projection, the latter equation is equivalent to

for all But this holds if and only if is a solution to

##### Remark

The next section shows that the equivalence of variational inequalities and fixed point problems is much stronger than the equivalence of nonlinear complementarity problems and fixed point problems because each nonlinear complementarity problem is a variational inequality defined on a closed convex cone.

#### Every variational inequality defined on a closed convex cone is equivalent to a complementarity problem

Let be a closed convex cone in the Hilbert space and a mapping. Then the nonlinear complementarity problem is equivalent to the variational inequality

##### Proof

Suppose that is a solution of Then and Hence

for all Therefore is a solution of

Conversely, suppose that is a solution of Then and

for all Choosing and in particular, we get a system of two inequalities that demands Thus for all equivalently, In conclusion, and Therefore is a solution to

#### Concluding the alternative proof

Since is a closed convex cone, the nonlinear complementarity problem is equivalent to the variational inequality which is equivalent to the fixed point problem

## Another fixed point problem providing solutions for variational inequalities and complementarity problems

Let be a closed convex set in the Hilbert space the identity mapping defined by and a mapping. Then, for any solution of the fixed point problem the projection of onto is a solution of the variational inequality

### Proof

Since is a solution of the fixed point problem , we have Thus, . Hence, is a solution of the fixed point problem and thus a solution of the variational inequality In particular, if is a closed convex cone, then the variational inequality becomes the complementarity problem

## Implicit complementarity problems

Let be a closed convex cone in the Hilbert space and two mappings. Recall that the dual cone of is the closed convex cone where is the
polar
of The **implicit complementarity problem** defined by
and the ordered pair of mappings is the problem

## Every implicit complementarity problem is equivalent to a fixed point problem

Let be a closed convex cone in the Hilbert space and two mappings. Then the implicit complementarity problem is equivalent to the fixed point problem where is the identity mapping defined by

### Proof

For all denote and Then

Suppose that is a solution of
Then with and
Via Moreau's theorem,
Therefore is a solution of

Conversely, suppose that is a solution of Then and, via Moreau's theorem,

Hence thus . Moreau's theorem also implies In conclusion, and Therefore is a solution of

### Remark

If in particular, we obtain the result
*every nonlinear complementarity problem is equivalent to a fixed point problem*.
But the more general result, *every implicit complementarity problem is equivalent to a fixed point problem*, has no known connection with variational inequalities. Using Moreau's theorem is therefore essential for proving the latter result.

## Nonlinear optimization problems

Let be a closed convex set in the Hilbert space and a function. The
**nonlinear optimization problem** defined by and
is the problem

## Any solution of a nonlinear optimization problem is a solution of a variational inequality

Let be a closed convex set in the Hilbert space and a differentiable function. Then any solution of the nonlinear optimization problem is a solution of the variational inequality where is the gradient of

### Proof

Let be a solution of and an arbitrary point. Then by convexity of we have hence and

Therefore is a solution of

## A convex optimization problem is equivalent to a variational inequality

Let be a closed convex set in the Hilbert space and a differentiable convex function. Then the nonlinear optimization problem is equivalent to the variational inequality where is the gradient of

### Proof

Any solution of is a solution of

Conversely, suppose that is a solution of By convexity of we have for all Therefore is a solution of

## Any solution of a nonlinear optimization problem on a closed convex cone is a solution of a nonlinear complementarity problem

Let be a closed convex cone in the Hilbert space and a differentiable function. Then any solution of the nonlinear optimization problem is a solution of the nonlinear complementarity problem

### Proof

Any solution of is a solution of which is equivalent to

## A convex optimization problem on a closed convex cone is equivalent to a nonlinear complementarity problem

**Theorem NOPT.** Let be a closed convex cone in the Hilbert space
and
a differentiable convex function. Then the nonlinear optimization problem is equivalent to the nonlinear complementarity problem

### Proof

is equivalent to which is equivalent to

## An implicit complementarity problem can be associated to an optimization problem

It follows from the definition of an implicit complementarity problem that is a solution of if and only the minimal value of subject to and is at

## Fat nonlinear programming problem

Let be a function, and a fat matrix of full rank Then the problem

is called **fat nonlinear programming problem**.

## Any solution of a fat nonlinear programming problem is a solution of a nonlinear complementarity problem defined by a polyhedral cone

Let be a differentiable function, and a fat matrix of full rank If is a solution of the fat nonlinear programming problem then is a solution of the nonlinear complementarity problem where is a particular solution of the linear system of equations is the polyhedral cone defined by

and is defined by

### Proof

Let be a solution of Then it is easy to see that is a solution of where is defined by It follows from Theorem NOPT that is a solution of because

### Remark

If is convex, then the converse of the above results also holds. In other words, where the first equivalence has a slightly different meaning than the other ones, but it should be self-explanatory.

Since a very large class of nonlinear programming problems can be reduced to nonlinear complementarity problems, the importance of nonlinear complementarity problems on polyhedral cones is obvious both from theoretical and practical point of view.

## Mixed complementarity problems

Let and be two Hilbert spaces and , where is an arbitrary closed convex cone in . Let , and . Then, the nonlinear complementarity problem is equivalent to the mixed complementarity problem defined by

### Proof

Indeed, is a simple equivalent reformulation of the nonlinear complementarity problem , by noting that .